2-[2-(1+4a)-5]=10-a

Solution for 2-[2-(1+4a)-5]=10-a equation:

Simplifying
2 + -1[2 + -1(1 + 4a) + -5] = 10 + -1a
2 + -1[2 + (1 * -1 + 4a * -1) + -5] = 10 + -1a
2 + -1[2 + (-1 + -4a) + -5] = 10 + -1a

Reorder the terms:
2 + -1[2 + -1 + -5 + -4a] = 10 + -1a

Combine like terms: 2 + -1 = 1
2 + -1[1 + -5 + -4a] = 10 + -1a

Combine like terms: 1 + -5 = -4
2 + -1[-4 + -4a] = 10 + -1a
2 + [-4 * -1 + -4a * -1] = 10 + -1a
2 + [4 + 4a] = 10 + -1a

Combine like terms: 2 + 4 = 6
6 + 4a = 10 + -1a

Solving
6 + 4a = 10 + -1a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'a' to each side of the equation.
6 + 4a + a = 10 + -1a + a

Combine like terms: 4a + a = 5a
6 + 5a = 10 + -1a + a

Combine like terms: -1a + a = 0
6 + 5a = 10 + 0
6 + 5a = 10

Add '-6' to each side of the equation.
6 + -6 + 5a = 10 + -6

Combine like terms: 6 + -6 = 0
0 + 5a = 10 + -6
5a = 10 + -6

Combine like terms: 10 + -6 = 4
5a = 4

Divide each side by '5'.
a = 0.8

Simplifying
a = 0.8